Zionsville named Best Place to Live in Indiana for 2019

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By Chris Bavender

For the second year in a row, HomeSnacks has named Zionsville as the Best Place to Live in Indiana. HomeSnacks collects data from the census, FBI, OpenStreetMaps and other sources into palatable studies to determine the rankings.

After analyzing 112 places in Indiana, HomeSnacks compiled its list of the best places to live. According to the site, Zionsville consistently ranks as one of the best places to live not only in Indiana, but in the nation.

Criteria used include median home values, median income, population density, unemployment rate, commute time, crime, education levels, health insurance coverage and poverty rates.

The ranking is no surprise to Zionsville mayor Tim Haak.

“Time after time we hear that residents choose Zionsville because of the high quality of life, the great schools, the 400-plus acres of parks and green space, the trails and the historic brick streets,” Haak said. “There is something unique here that we see other towns and cities strive to accomplish.”

According to HomeSnacks, homes in Zionsville are the most expensive in the state, with an average value of $343,400.

“We’re not elitists, nor are we saying that big homes mean a better place to live,” HomeSnacks contributing writer Chris Kolmar said. “But price reflects demand, and simply put, a lot of people want to live in Zionsville if they can afford it.”

HomeSnacks found that Zionsville residents have the highest income in the state and the town has Indiana’s overall lowest crime rate.

“Zionsville has done a great job maintaining its rich history and small-town feel, while at the same time providing all the amenities and attractions that make families want to live here,” Haak said.

The other top 10 municipaties on the list are:

2 – Carmel

3 – St. John

4 – Dyer

5 – Noblesville

6 – Westfield

7 – Munster

8 – White

9 – Brownsburg

10 – Jasper


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